this post was submitted on 05 Jul 2025
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Programming

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[โ€“] The2b@lemmy.vg 2 points 1 week ago (1 children)

The hashes not being there isn't particularly relevant within a hash function outputting a specific size. If your hash function is always 64 bits for example, the fact that you have 3/4th of them not exist means you should be operating as if its a 16 bit hash, not a 64 bit hash. If you still do this math based on the 64 bits outputted (2^64 boxes) you'd arrive at very inaccurate numbers.

[โ€“] anton@lemmy.blahaj.zone 3 points 1 week ago

That would be 62 bit, not 16 bit.