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Infallible Code (europe.pub)

submitted 2 days ago by sirico@feddit.uk to c/programmerhumor@lemmy.ml

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[–] redxef@feddit.org 36 points 1 day ago (3 children)

def is_even(n: int) -> bool:
    if n < 0:
        return is_even(-n)
    r = True
    for _ in range(n):
        r = not r
    return r

[–] OddMinus1@sh.itjust.works 3 points 21 hours ago* (last edited 21 hours ago) (1 children)

Could also be done recursive, I guess?

boolean isEven(int n) {
  if (n == 0) {
    return true;
  } else {
    return !isEven(Math.abs(n - 1));
  }
}

[–] dragonlobster@programming.dev 2 points 1 day ago

He loves me, he loves me not

[–] vandsjov@feddit.dk 1 points 1 day ago

No, no, I would convert the number to a string and just check the last char to see if it was even or not.