this post was submitted on 09 Apr 2025
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Antimatter doesn't really do anything by it's own, but if we let 1 kg react with 1 kg of matter (non-anti-matter), we get E = mc^2^ with m = 2 kg. So 1.8 * 10^17^ J, or 1.8 * 10^11^ MJ. If we assume that 10 MJ/kg is represented by about 1 cm, the bar would have to be 1.8 * 10^10^ cm or about 1.8 * 10^8^ m. A standard A4 piece of paper is about 30 cm tall, so 6.0 * 10^8^ A4 papers are needed. I.e. 600 million papers.
So we definitely have enough paper, but it would be a very tall stack.