this post was submitted on 27 May 2025
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Explain Like I'm Five
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Small correction, but this bit isn't quite correct:
During the time that you are just below light speed at a constant velocity, clocks that are "stationary" will appear to be moving slow to you. And clocks moving with you will appear to be running slow for a "stationary" observer. As I mentioned in a comment in another reply, the trip would feel short to you because the distance to your destination would contract to nearly zero. "Fast forwarding" (ie, having both you and a stationary observer agree that more time has passed on the stationary observer's clock) would happen during the periods of acceleration/deceleration at the beginning and end of the trip.