this post was submitted on 12 Mar 2025
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[–] CompassRed@discuss.tchncs.de 1 points 2 months ago (1 children)

Interesting. I think it isn't unital either otherwise Ω=0.

0=Ω+Ω=Ω+ΩΩ=Ω(1+Ω)=ΩΩ=Ω

[–] Leate_Wonceslace@lemmy.dbzer0.com 1 points 2 days ago (1 children)

Someone else had the same observation, but it is unital. Keep in mind that it isn't associative; you can't pull out the Omega like that.

[–] CompassRed@discuss.tchncs.de 1 points 2 days ago

The definition I'm aware of for non associative algebras has them distributive by default, so I believe the chain of equations is valid.