this post was submitted on 04 Jun 2026
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Science Memes

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[–] cannedtuna@lemmy.world 80 points 1 week ago (9 children)
[–] whotookkarl@lemmy.dbzer0.com 210 points 1 week ago (5 children)

When sailing boats pushed for speed they ended up hitting an unexpected speed barrier. As you increase velocity the break wave created by the bow of the ship elongates until the length of the ship is at 1 wavelength, then the hull drag prevents further acceleration. For a 50 meter ship it's about 17 knots. You can get much faster lifting the boat from the water as you gain speed with an underwater wing, the current max speed was set 47 years ago at ~276 knots. But that's only because they can remove the hull from the high drag environment and is extremely dangerous to attempt to break. The speed of light is nothing like that because spacetime itself can stretch and squish, I just wanted to talk about boats for a bit.

[–] cannedtuna@lemmy.world 41 points 1 week ago

Still very interesting

[–] icelimit@lemmy.ml 34 points 1 week ago* (last edited 1 week ago)

So you're saying, we need to jump the spaceship out from space/time. With a wing.

[–] Sylvartas@lemmy.dbzer0.com 24 points 1 week ago (1 children)

I'm not even mad because now I get why and how these competition multihull boats basically fly above water while keeping like 1% of the boat in water

[–] anomnom@sh.itjust.works 12 points 1 week ago

Those ones are reaching a new speed limit as well, the cavitation around the hydrofoil starts at a certain speed/angle and stalls the foil, which then abruptly drops the hull back into the water.

I’ve been wondering how long before the equivalent of variable swept wings will be added to the cup boats.

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[–] FuglyDuck@lemmy.world 43 points 1 week ago* (last edited 1 week ago) (1 children)

You have two observers, moving directly opposite each other.

Each has a flashlight pointing back at the other.

The speed of the light from those torched is the same for both observers.

(Instead the light would be red-shifted.)

Add a third observer, stationary to one and moving towards the other. As the third observer passes that observer, the speed of light from their flashlight never changes, and it’s the same speed as from the other two. (Instead it would go from being blue shifted to red shifted.)

[–] scbasteve@lemmy.world 51 points 1 week ago (4 children)

This adds substantially more questions than it answers.

[–] technohacker@programming.dev 35 points 1 week ago

-Scientists after discovering General Relativity

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[–] panda_abyss@lemmy.ca 53 points 1 week ago (9 children)

Okay, but what if I go the speed of light minus 1m/s and shine a flashlight, can I catch the photons?

[–] smiletolerantly@awful.systems 206 points 1 week ago (1 children)

No

That's not a physics statement btw. I just think that you, personally, are too slow to be able to do that. Offense intended.

[–] a_non_monotonic_function@lemmy.world 23 points 1 week ago (2 children)

That may seem harsh to the casual reader, but it's 100% true in this case.

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[–] OwOarchist@pawb.social 73 points 1 week ago (2 children)

You can catch the photons just fine without needing to go absurdly fast. Just put your hand in front of the flashlight beam, and you'll catch lots of them.

[–] homesweethomeMrL@lemmy.world 51 points 1 week ago

Physicists hate this one weird trick

[–] Evil_Shrubbery@thelemmy.club 16 points 1 week ago* (last edited 1 week ago) (1 children)

without needing to go absurdly fast

... I would actually argue that for a human catching anything at c-1m/s is impossible. Except catching death perhaps.

Not going "absurdity" fast is more of a requirement.

[–] OwOarchist@pawb.social 15 points 1 week ago (1 children)

You're already going c-1m/s if compared to the right reference frame.

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[–] nexguy@lemmy.world 43 points 1 week ago (1 children)

Light ALWAYS travels away from you at the speed of light no matter how fast you and your flashlight are going. Something has to give and that is time. It may look to outside observers, not traveling that fast along with you, that light is going 1 m/s faster than you... but you would also appear to be moving in super slow motion trying to reach out for the beam. The faster you go the slower time moves for you.

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[–] webghost0101@sopuli.xyz 22 points 1 week ago (2 children)

I think the answer is that you are only traveling at almost light speed from reference frame of your start position.

The light of the lamp travels at light speed from your own reference speed which to you in a vacuum is 0.

Anyone correct if wrong please?

[–] BluJay320@lemmy.blahaj.zone 26 points 1 week ago* (last edited 1 week ago)

Correct. Physics gets really, really weird at relativistic speeds. Something to keep in mind is that the speed of light isn’t actually the speed of light itself, but rather the speed of causality - the universe’s hard limit at which any interactions can occur. Even if you are traveling at .99c from a certain reference frame, space time itself warps in such a way that light traveling away from you is still measured at 1c

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[–] pomegranatefern@sh.itjust.works 22 points 1 week ago

Nope. In your frame of reference, they will still be moving at the speed of light.

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[–] 5too@lemmy.world 40 points 1 week ago* (last edited 1 week ago) (12 children)

A bit late to the party, but I'll try anyway!

So, first, speed is distance over time. Miles per second, kilometers per hour, whatever.

Consider a person rocketing by a planet in a little spaceship at a good fraction of the speed of light. To amuse themselves, they're bouncing a ball between two paddles on opposite walls of their craft. The ball describes a path like:

O--------O

--O----O

-----O

Of course, to a person on a planet they're blasting past, the path looks different - the ship moves a long way between each bounce, so they see:

O----------------------------------O

-------O------------------O

----------------O

The thing is, both of these are correct from each point of view - from each reference frame. For the shipboard person, the ball moves the width of the ship, and for the planetside person, it covers the distance the ship traveled in the bounce (plus some for the width).

Now, swap the ball for a photon, which always moves at the same speed. The distance the photon travels from the two points of view - the two reference frames - is different, so the time component of the photon's measured speed must change as well because the photon's speed remains the same! Each side sees the photon moving at the same speed, despite the difference in distance traversed each pov sees - which means each must also have a different measurement of the time involved!

So, time is compressed on the spaceship relative to the planet - from the ship, the planetside observer is moving very fast, while to the planetside observer, the space pilot is moving in slow motion. The speed of the photon is universal - it's the distance it travels between bounces, and therefore how long it takes to bounce, that differs between their perspectives.

[–] MJKee9@lemmy.world 17 points 1 week ago (1 children)

And that is what is meant by time dilation, and why Matthew Mcconaughey was younger than his grandkids. His balls took longer to bounce......

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[–] yesman@lemmy.world 33 points 1 week ago (8 children)

I think it's neat that Newton is taught first. As in: gravity is a function of mass. Because that works in so many scenarios.

But then you learn that gravity bends light and that photons have no mass.

So.... Gravity isn't a force, it's more like going downhill... in the dimension of time.

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[–] whitedovebooks@lemmy.world 31 points 1 week ago (5 children)

If you were on a train that was travelling at 60 mph and you threw a ball (inside the train) and the ball was travelling at 10 mph (inside the train), then the ball would objectively be travelling at 70 mph. Any observer (outside the train) would be able to understand why it looks like 10 mph inside the train and 70 mph outside the train.

Are you with me?

Okay, so the same thing does not happen with light! If you turn on a flashlight (inside the train), the light would be travelling at 670,616,629 mph regardless of whether the train was stationary or moving. So an observer outside the train would see the light travelling at the same speed as an observer inside the train. Even if the train was some supersonic invention from the future, the light inside the train would still be travelling at 670,616,629 mph - not 670,616,629 mph plus the speed of the train. And both inside and outside the train, observers would see the light as travelling at that speed. That's the big thing to get hold of!

How can this possibly be the case?

The answer is that time itself actually slows down when we are in motion. At low speeds, the effect is negligible, but the closer we get to the speed of light, the more the effect becomes observeable, until, when we are travelling at the speed of light, time stands still. If we were able to go faster than the speed of light, we would be travelling backwards through time.

[–] 87Six@lemmy.zip 14 points 1 week ago (1 children)

Thanks for fucking up my mind so I can't get anything done at work for the rest of the day lol

[–] Zink@programming.dev 7 points 1 week ago (3 children)

Oh it gets even weirder than that.

One observer can see two events happen simultaneously while another sees them happen at different times.

And EVEN WORSE than that, thanks to length contraction at relativistic speeds, you could have one observer think that a train is contained entirely within a tunnel, but another observer sees the train sticking out both ends of the tunnel at the same time without ever fitting entirely within it.

and/or: One observer objectively masures that object A is longer than object B, while another observer objectively measures that object B is longer than object A.

The two observers are not just hanging out together, of course. They are moving ridiculously fast relative to one another.

The speed of causality is a hell of a drug.

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[–] UnrepententProcrastinator@lemmy.ca 8 points 1 week ago (2 children)
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[–] LovableSidekick@lemmy.world 24 points 1 week ago* (last edited 1 week ago) (1 children)

The speed of light isn't even really a speed, it's a property of space itself.

[–] Spooge@lemmy.world 16 points 1 week ago (7 children)
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[–] D_C@sh.itjust.works 23 points 1 week ago (10 children)

Ok, firstly I'm not very smart. Secondly I don't understand the meme AND don't understand the explanations in the comments.
Can anyone actually dumb it down so a stupid person like me can understand it?

[–] 87Six@lemmy.zip 8 points 1 week ago

Thing go slow - > speed act normal, speed add up between POV's, speed make sense AF

Thing light fast like - > speed act fucky wucky, speed don't add up at all between POV's, speed so fast make time fucky wucky too

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[–] Small_Quasar@lemmy.world 10 points 1 week ago (15 children)

Whilst we're at it can someone explain;

A) a photon travels at the speed of light because it is massless, right? But doesn't E=mc² teach us that mass and energy are somewhat interchangeable? How can a photon have energy but no mass?

B) I'm willing to accept it as fact when smarter people tell me that FTL is impossible because, amongst other things, it will break causality. It makes perfect sense to me that the universe needs to have some unbreakable rules for things to remain consistent. But I've never been able to grasp exactly why it would break causality.

[–] Blue_Morpho@lemmy.world 14 points 1 week ago

But I’ve never been able to grasp exactly why it would break causality.

It's what I might call inferred logic. It's not that traveling faster than light "breaks causality" it's that light is observed to be constant in all reference frames. From that observation you build a system of motion which requires that nothing can travel faster than light. In that mathematical system, if you break that rule then the math says that you must go backwards in time to go faster than light.

So the "causality" is a side effect of the math system you created based around the rule that light is constant in all reference systems.

It's like if you created a math system where you observed A=1 and let B=1 and state that A+B=2. Then someone says but what if A+B = -1. Your reply would be that means B = -2 because we observed A = 1 and B can be anything so if we add A + B and get -1 B must be -2. If B represented time you'd say, "Well that means you have negative time!" But it's just the math and if you give physically impossible inputs you get physically impossible outputs.

[–] marcos@lemmy.world 12 points 1 week ago

But doesn’t E=mc² teach us that mass and energy are somewhat interchangeable?

There are two ways to read that equation. Either you use the instant mass, that changes with the object's speed and has an undefined result for anything moving at the speed of light (this is the one Einstein wrote in awe about), or you use the rest mass and that's the half of the equation that doesn't consider the object's speed (this is the one everybody actually uses).

On the second case, the complete equation is E² = (mc²)² + (pc)² where p is the momentum.

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[–] LordCrom@lemmy.world 10 points 1 week ago (10 children)

And remember, a photon of light does not experience time. Time only applies to mass. When a photon is emitted traveling at the speed of light, it is eventually absorbed by something, eglight from the sun hitting your eye. The photon of ligjt, from the photon POV is emitted and absorbed in the same instance.

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